Y=-0.02x^2+1.2x+0.605

Solution for Y=-0.02x^2+1.2x+0.605 equation:

=-0.02Y^2+1.2Y+0.605

We move all terms to the left:

-(-0.02Y^2+1.2Y+0.605)=0

We get rid of parentheses

0.02Y^2-1.2Y-0.605=0

a = 0.02; b = -1.2; c = -0.605;
Δ = b2-4ac
Δ = -1.22-4·0.02·(-0.605)
Δ = 1.4884
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.2)-\sqrt{1.4884}}{2*0.02}=\frac{1.2-\sqrt{1.4884}}{0.04}
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.2)+\sqrt{1.4884}}{2*0.02}=\frac{1.2+\sqrt{1.4884}}{0.04}
$